The current through a conductor at 0°C and 100°C, for the same voltage source, is 2 A and 1.2 A respectively. The current at 50°C i s ______ × 10² mA.

Question

G1 Physics · Accepted Answer

For the same source, I₀R₀ = I₁₀₀R₁₀₀ and R₁₀₀ = R₀(1 + 100α) Thus, 2 = 1.2(1 + 100α) 1 + 100α = 5/3 So, 50α = 1/3 At 50°C: R₅₀ = R₀(1 + 50α) = (4/3)R₀ Hence, I₅₀ = I₀R₀/R₅₀ = 2/(4/3) = 1.5 A = 15×10² mA Final value: 15