Position of a particle is x = t + 1/t metre, t>0. Its average speed between t=1/2 s and t=2 s is:
Options

Question

Position of a particle is x = t + 1/t metre, t>0. Its average speed between t=1/2 s and t=2 s is:

G1 Physics · Accepted Answer

v = dx/dt = 1−1/t². v=0 at t=1 s. Positions: x(1/2)=1/2+2=5/2, x(1)=2, x(2)=2+1/2=5/2. Total distance = 1/2 + 1/2 = 1 m. Total time = 2−1/2 = 3/2 s. Average speed = 1/(3/2) = 2/3 m s⁻¹.