A 10 kg mass hangs vertically from a rope. A horizontal force is applied at some point on the rope so that the upper rope segment makes 45° with the roof while the mass remains in equilibrium. Take g=10 m s⁻². The horizontal force is:
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Question

A 10 kg mass hangs vertically from a rope. A horizontal force is applied at some point on the rope so that the upper rope segment makes 45° with the roof while the mass remains in equilibrium. Take g=10 m s⁻². The horizontal force is:

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G1 Physics · Accepted Answer

At the junction, the lower vertical tension is 100 N. For the upper tension at 45°, its vertical component must be 100 N, so its horizontal component is also 100 N. Hence the applied horizontal force is 100 N.