A 200 g block is kept stationary on a smooth 60° incline by applying the minimum horizontal force F=√x N. Take g=10 m s⁻². Find x.

Question

G1 Physics · Accepted Answer

Along the incline, F cos60°=mg sin60°. Thus F=mg tan60°=0.2×10×√3=2√3 N, so x=F²=12.