A particle starts from the point (0m, 8m) and moves with uniform velocity of ˆ 3 i m/s. After 5 seconds, the angular velocity of the particle about the origin will be:

Question

G1 Physics · Accepted Answer

At t=5 s the particle is at r⃗=15î+8ĵ m and has v⃗=3î m/s. Angular speed about the origin is ω=|r⃗×v⃗|/r² = |(15î+8ĵ)×3î|/(15²+8²)=24/289 rad/s. Hence option C.