In YDSE with wavelength λ, what path difference corresponds to a point having half the peak intensity?
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Question

In YDSE with wavelength λ, what path difference corresponds to a point having half the peak intensity?

G1 Physics · Accepted Answer

For equal slit intensities, I=Iₘₐₓcos²(πδ/λ). If I=Iₘₐₓ/2, then cos²(πδ/λ)=1/2. Hence δ=(2n+1)λ/4. Option B.