Two particles are in SHM on the same straight line with amplitudes A and 2A and the same angular frequency ω. When the first particle is at a distance A/√2 from the origin and moving towards the mean position, the other particle is at the extreme position on the other side of the mean position. Find the phase difference.
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Question

Two particles are in SHM on the same straight line with amplitudes A and 2A and the same angular frequency ω. When the first particle is at a distance A/√2 from the origin and moving towards the mean position, the other particle is at the extreme position on the other side of the mean position. Find the phase difference.

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G1 Physics · Accepted Answer

For the first particle at x=A/√2 while moving toward the mean, its phase can be taken as 3π/4. The second particle is at the opposite extreme, phase 3π/2. The phase difference is 3π/2−3π/4=3π/4=135°. Correct answer: C.