A particle performing SHM is found at its equilibrium at t = 1 s and it is found to have a speed of 0.25 m s⁻¹ at t = 2 s If the period of oscillation is 6 s Calculate amplitude of oscillation
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A particle performing SHM is found at its equilibrium at t = 1 s and it is found to have a speed of 0.25 m s⁻¹ at t = 2 s If the period of oscillation is 6 s Calculate amplitude of oscillation

G1 Physics · Accepted Answer

At t=1 s the particle is at equilibrium. One second later, with T=6 s, the phase advances by π/3. Thus v=Aω cos(π/3)=A(π/3)(1/2)=Aπ/6. Given v=0.25 m s⁻¹, A=1.5/π=3/(2π) m. Correct answer: A.