A particle executes SHM with amplitude 2 cm. At displacement 1 cm from the mean position, the numerical value of the magnitude of acceleration equals the numerical value of the magnitude of velocity. The frequency of SHM (in s⁻¹) is:
Options

Question

A particle executes SHM with amplitude 2 cm. At displacement 1 cm from the mean position, the numerical value of the magnitude of acceleration equals the numerical value of the magnitude of velocity. The frequency of SHM (in s⁻¹) is:

Options

G1 Physics · Accepted Answer

A=0.02 m and x=0.01 m. In SHM, |a|=ω²x and v=ω√(A²−x²). Equating numerical values: 0.01ω²=ω√(0.0004−0.0001)=0.01√3 ω. Hence ω=√3 rad s⁻¹ and f=√3/(2π) s⁻¹. Correct answer: C.