Kinetic energy of a particle executing SHM is pv² and potential energy is qx², where v is the speed at distance x from the mean position. Its time period is:
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Kinetic energy of a particle executing SHM is pv² and potential energy is qx², where v is the speed at distance x from the mean position. Its time period is:

G1 Physics · Accepted Answer

pv²=(1/2)mv² gives m=2p. Also qx²=(1/2)kx² gives k=2q. Therefore T=2π√(m/k)=2π√(p/q). Correct answer: B.