A horizontal spring–block system executes SHM, x = A sin(ωt + φ), with A = 10 cm, φ = 0 and angular frequency ω. M = 25 kg, k = 2500 N m⁻¹. At t = t₁ where ωt₁ = 30°, a mass m = 75 kg is gently placed on the block. The collision is perfectly inelastic and m remains at rest relative to M.

Physics · Simple Harmonic Motion

JEE MainsAdvanced

A horizontal spring–block system executes SHM, x = A sin(ωt + φ), with A = 10 cm, φ = 0 and angular frequency ω. M = 25 kg, k = 2500 N m⁻¹. At t = t₁ where ωt₁ = 30°, a mass m = 75 kg is gently placed on the block. The collision is perfectly inelastic and m remains at rest relative to M.

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Sub-question 1

The new angular frequency of the system will be :

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Sub-question 2

The total energy of system after collision at any moment of time is :- 175 88

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