In the given figure, spring and pulleys are massless. Block A is performing SHM of amplitude 1 m and time period π s If block B remains at rest, then minimum value of coefficient of friction between block B and surface will be µ. Fill 10µ in OMR sheet. (g = 10 m s⁻²)

Question

G1 Physics · Accepted Answer

Block A has T=π s, so ω=2 rad s⁻¹ and maximum acceleration=ω²A=4 m s⁻². With block B fixed, the pulley constraint makes the support acceleration half that of A. The tension needed in the string reaches its largest value when A accelerates downward: Tₘₐₓ=m(g+4)=14m. Block B has normal reaction 2mg=20m, so μₘᵢₙ=14/20=0.7. Hence 10μ=7.