A particle executes SHM with time period T and amplitude A. The maximum possible average velocity in time T/4 is:
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Question

A particle executes SHM with time period T and amplitude A. The maximum possible average velocity in time T/4 is:

G1 Physics · Accepted Answer

Over a time T/4, the largest possible displacement change is the chord corresponding to a phase change π/2: Δxₘₐₓ=√2 A. Therefore maximum average velocity=Δxₘₐₓ/(T/4)=4√2 A/T. Correct option: 4.