The displacement is x = 5 sin(2t), with x in metres and t in seconds. A simple pendulum has the same period. If its length is l l l , find 10 l l l .
Physics · Simple Harmonic Motion
JEE Mains

Question

The displacement is x = 5 sin(2t), with x in metres and t in seconds. A simple pendulum has the same period. If its length is l l l , find 10 l l l .

G1 Physics · Accepted Answer

x=5 sin2t has angular frequency 2 rad s⁻¹. A pendulum with the same period has √(g/l)=2, so l=g/4=10/4=2.5 m. Hence 10l=25.