A particle performing SHM with period T is at x = +A/2 and moving towards the positive extreme. The first time after which it comes to rest is T/N. Find N.
Physics · Simple Harmonic Motion
JEE Mains

Question

A particle performing SHM with period T is at x = +A/2 and moving towards the positive extreme. The first time after which it comes to rest is T/N. Find N.

G1 Physics · Accepted Answer

At x=A/2 while moving toward +A, phase can be π/6. The next rest point is +A at phase π/2, so phase change is π/3. Thus Δt=(π/3)/(2π/T)=T/6. Since Δt=T/N, N=6.