In the shown arrangement, what should be the hanging mass m so that block A of mass 1 kg slides up a 37° rough incline with constant velocity? The coefficient of friction is μ = 0.5. Take g = 10 m s⁻².

Question

G1 Physics · Accepted Answer

For constant speed of A, net force along the incline is zero. T = mₐg sin37° + μmₐg cos37° = 1×10(3/5)+0.5×1×10(4/5)=6+4=10 N. The hanging mass also moves with constant speed, so m g = T = 10 N. Hence m = 1 kg.