A conveyor belt moves at constant speed 2 m s⁻¹. A box is gently dropped onto it; the friction coefficient is μ=0.5. Find distance the box moves relative to the belt until it stops slipping. Use g=10 m s⁻².
Options

Question

A conveyor belt moves at constant speed 2 m s⁻¹. A box is gently dropped onto it; the friction coefficient is μ=0.5. Find distance the box moves relative to the belt until it stops slipping. Use g=10 m s⁻².

Options

G1 Physics · Accepted Answer

Friction accelerates the box at a=μg=5 m s⁻². Relative to the belt, initial velocity is −2 m s⁻¹ and relative acceleration +5 m s⁻². When relative velocity becomes zero, relative distance magnitude =uᵣₑₗ²/(2aᵣel)=4/10=0.4 m. Answer: D.