The displacement of a particle executing simple harmonic motion is y = A₀ + A sin(ωt) + B cos(ωt). Then the amplitude of its oscillation is:
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The displacement of a particle executing simple harmonic motion is y = A₀ + A sin(ωt) + B cos(ωt). Then the amplitude of its oscillation is:

G1 Physics · Accepted Answer

Step 1: The constant A₀ shifts the equilibrium position; it does not contribute to oscillation amplitude. Step 2: Write A sin(ωt) + B cos(ωt) = R sin(ωt + φ). Step 3: Matching coefficients gives R cosφ = A and R sinφ = B. Step 4: Squaring and adding: R² = A² + B², so amplitude R = √(A² + B²). Final answer: (A) √(A² + B²).