A particle executing simple harmonic motion of amplitude 5 cm has maximum speed 31.4 cm/s. The frequency of its oscillation is:
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A particle executing simple harmonic motion of amplitude 5 cm has maximum speed 31.4 cm/s. The frequency of its oscillation is:

G1 Physics · Accepted Answer

Step 1: For SHM, maximum speed vₘₐₓ = ωA = 2πfA. Step 2: A = 5 cm and vₘₐₓ = 31.4 cm s⁻¹. Step 3: f = vₘₐₓ/(2πA) = 31.4/(2π × 5) ≈ 1.00 Hz. Final answer: (D) 1 Hz.