A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations, when a mass of 2 kg is suspended by it, is:
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Question

A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations, when a mass of 2 kg is suspended by it, is:

G1 Physics · Accepted Answer

Step 1: From Hooke’s law, F = kΔx, so k = F/Δx. Step 2: With Δx = 5 cm = 0.05 m, k = 10/0.05 = 200 N m⁻¹. Step 3: For a mass–spring system, T = 2π√(m/k). Step 4: T = 2π√(2/200) = 2π/10 ≈ 0.628 s. Final answer: (D) 0.628 s.