The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be:
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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be:

G1 Physics · Accepted Answer

Step 1: The initial spring-mass period is T = 2π√(M/k). Step 2: Adding another identical mass doubles the oscillating mass to 2M. Step 3: T′ = 2π√(2M/k) = √2 × 2π√(M/k) = √2T. Final answer: (D) √2T.