A particle executing simple harmonic motion has a kinetic energy K₀ cos²(ωt). The maximum values of the potential energy and total energy are respectively:
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A particle executing simple harmonic motion has a kinetic energy K₀ cos²(ωt). The maximum values of the potential energy and total energy are respectively:

G1 Physics · Accepted Answer

Step 1: Total mechanical energy E in undamped SHM is conserved. Step 2: Kinetic energy K(t) = K₀cos²(ωt); its maximum is K₀ when cos²(ωt) = 1. Step 3: At the equilibrium position the potential energy is zero, so E = Kₘₐₓ = K₀. Step 4: At a turning point kinetic energy vanishes and potential energy reaches Uₘₐₓ = E = K₀. Final answer: (C) K₀ and K₀.