An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 10⁵ N C⁻¹. It experiences a torque equal to 4 N-m. Calculate the magnitude of charge on the dipole if the dipole length is 2 cm.
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Question

An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 10⁵ N C⁻¹. It experiences a torque equal to 4 N-m. Calculate the magnitude of charge on the dipole if the dipole length is 2 cm.

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G1 Physics · Accepted Answer

Step 1: Torque magnitude on dipole τ = pE sinθ = qlE sinθ. Step 2: Substitute 4 = q(0.02)(2 × 10⁵)sin30°. Step 3: Denominator = 0.02 × 200000 × 0.5 = 2000. Step 4: q = 4/2000 = 0.002 C = 2 mC.