For the circuit of four capacitors in a bridge shown in figure, the equivalent capacitance between terminal X and terminal Y is: [Diagram: Image]
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For the circuit of four capacitors in a bridge shown in figure, the equivalent capacitance between terminal X and terminal Y is: [Diagram: Image]

G1 Physics · Accepted Answer

Step 1: The symmetric capacitive bridge is balanced and middle branch has no potential difference. Step 2: Each remaining branch contains two 2 μF capacitors in series, giving Cᵦᵣₐₙ𝒸ₕ = (2 × 2)/(2 + 2) = 1 μF. Step 3: Two such branches are in parallel: C(eq) = 1 + 1 = 2 μF.