Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:
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Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be:

G1 Physics · Accepted Answer

Step 1: Three identical capacitors in series: 1/C(eq) = 1/C + 1/C + 1/C = 3/C. Thus C(eq) = C/3. Step 2: Voltage divides equally across identical capacitors. Step 3: Each can sustain V, so maximum overall voltage = 3V.