For the shown ideal diode network containing 30 Ω, 20 Ω resistors and a 5 V battery, find supply current.
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Question

For the shown ideal diode network containing 30 Ω, 20 Ω resistors and a 5 V battery, find supply current.

G1 Physics · Accepted Answer

Source diagram has two antiparallel diode branches. With the stated battery polarity D₁ is forward biased and D₂ is reverse biased. Thus only the D₁ branch (30 Ω) conducts in series with the bottom 20 Ω resistor. R_eq = 30 + 20 = 50 Ω. Supply current I = 5 V/50 Ω = 0.10 A = 5/50 A. Final answer: Option B; printed key marks C, which disagrees with the original circuit calculation.