In the three-particle arrangement where equal masses m are at r, 2r and 3r on a radial string, take m=1 kg, r=0.5 m and ω=2 rad/s. If the innermost string tension T₁=N newton, find N.
Physics · Circular Motion · centripital force and centrifugal force
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Question

In the three-particle arrangement where equal masses m are at r, 2r and 3r on a radial string, take m=1 kg, r=0.5 m and ω=2 rad/s. If the innermost string tension T₁=N newton, find N.

G1 Physics · Accepted Answer

From the force balance for the three masses, T₁ = 6mω²r. Substituting m=1 kg, ω=2 rad/s and r=0.5 m: T₁ = 6×1×(2²)×0.5 = 6×4×0.5 = 12 N. Therefore N=12.