An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = +2 m, its velocity is -4ĵ m s⁻¹. The object’s velocity v and acceleration a at x = -2 m will be:
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Question

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = +2 m, its velocity is -4ĵ m s⁻¹. The object’s velocity v and acceleration a at x = -2 m will be:

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G1 Physics · Accepted Answer

The radius is 2 m and speed is 4 m s⁻¹, so centripetal acceleration magnitude is v²/r = 16/2 = 8 m s⁻². Since motion at x = +2 m is downward, the motion is clockwise. At x = −2 m, velocity is upward: v = 4ĵ m s⁻¹. Centripetal acceleration points toward the origin, i.e. +x direction: a = 8î m s⁻².

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = +2 m, its velocity is −4ĵ m s⁻¹. The object’s velocity v and acceleration a at x = −2 m will be: