A stone of mass 1 kg is tied to the end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity the stone can have without breaking the string while rotating in horizontal plane is:
Options

Question

A stone of mass 1 kg is tied to the end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity the stone can have without breaking the string while rotating in horizontal plane is:

Options

G1 Physics · Accepted Answer

For horizontal circular motion, maximum tension provides centripetal force: T = mv²/r. Thus v = √(Tr/m) = √(400×1/1) = 20 m s⁻¹.