A sample of gas at temperature T is adiabatically expanded to double its volume. The work done by the gas in the process is: [γ = 3/2]
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A sample of gas at temperature T is adiabatically expanded to double its volume. The work done by the gas in the process is: [γ = 3/2]

G1 Physics · Accepted Answer

For an adiabatic process, T V ( γ − 1 ) = c o n s t a n t . V^(γ-1)=constant. V ( γ − 1 ) = co n s t an t . With γ-1=1/2 and V₂=2V₁, T₂=T/√2. Work done by one mole is W = R(T₁-T₂)/(γ-1) = 2RT(1-1/√2) = RT(2-√2).