A sample of gas at temperature T is adiabatically expanded to double its volume. The work done by the gas in the process is: [γ = 3/2]
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A sample of gas at temperature T is adiabatically expanded to double its volume. The work done by the gas in the process is: [γ = 3/2]

G1 Physics · Accepted Answer

For an adiabatic process, TV^(γ−1)=constant. With γ−1=1/2 and V₂=2V₁, T₂=T/√2. Work done by one mole is W = R(T₁−T₂)/(γ−1) = 2RT(1−1/√2) = RT(2−√2).