A block of mass 5 kg is initially at rest on a rough horizontal table. A force of 30 N is applied parallel to the table and the block slides through 50 m in 10 s. The coefficient of kinetic friction is: [g = 10 m s⁻²]
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Question

A block of mass 5 kg is initially at rest on a rough horizontal table. A force of 30 N is applied parallel to the table and the block slides through 50 m in 10 s. The coefficient of kinetic friction is: [g = 10 m s⁻²]

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G1 Physics · Accepted Answer

From s = (1/2)at², 50 = (1/2)a(100), so a=1 m s⁻². Net force ma=5 N. Hence 30−μ(5×10)=5, giving μ=25/50=0.5.