As shown in the figure, two parallel plate capacitors of equal plate area 200 cm² are joined with unequal separations a and b. The equivalent capacitance is xε₀ F. Find x. Image
Physics · Circular Motion
JEE Mains 6 April 2023 Shift 2 Evening Shift

Question

As shown in the figure, two parallel plate capacitors of equal plate area 200 cm² are joined with unequal separations a and b. The equivalent capacitance is xε₀ F. Find x. Image

G1 Physics · Accepted Answer

For each parallel-plate capacitor, C = ε₀A/d Using the two plate separations a and b shown in the figure, first write C₁ = ε₀A/a and C₂ = ε₀A/b Then combine C₁ and C₂ according to the connection shown in the figure. Substituting the given area A = 200 cm² and the indicated separations gives C(eq) = 5ε₀ F Therefore x = 5. Final value: 5