A particle executes SHM of amplitude A along the x-axis. At t = 0, its position is x = A/2 and it moves along the positive x-axis. If x = A sin(ωt + δ), the value of δ is:
Options

Question

A particle executes SHM of amplitude A along the x-axis. At t = 0, its position is x = A/2 and it moves along the positive x-axis. If x = A sin(ωt + δ), the value of δ is:

G1 Physics · Accepted Answer

At t = 0: A sinδ = A/2 Therefore, sinδ = 1/2 Possible values are δ = π/6 or 5π/6. Velocity is v = Aω cos(ωt + δ) At t = 0 the particle moves in the positive x-direction, so cosδ > 0. Therefore, δ = π/6 Hence option D follows.