Surface tension of a soap solution is 3.5 × 10⁻² N m⁻¹. Find the work required to increase a soap-bubble radius from 10 cm to 20 cm, expressed a s ______ × 10⁻⁴ J. Take π = 22/7.

Physics · Properties of solid and fluid · properties of fluid and surface tension

JEE Mains11 April 2023Shift 2Evening Shift

Surface tension of a soap solution is 3.5 × 10⁻² N m⁻¹. Find the work required to increase a soap-bubble radius from 10 cm to 20 cm, expressed as ______ × 10⁻⁴ J. Take π = 22/7.