If x = 5 sin(πt + π/3) m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are:
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Question

If x = 5 sin(πt + π/3) m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are:

G1 Physics · Accepted Answer

Step 1: Compare x = 5 sin(πt + π/3) with x = A sin(ωt + φ). Step 2: Amplitude A = 5 m and angular frequency ω = π rad s⁻¹. Step 3: T = 2π/ω = 2π/π = 2 s. Final answer: (A) 5 m, 2 s.