A simple pendulum performs SHM x = 0 with amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
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A simple pendulum performs SHM x = 0 with amplitude a and time period T. The speed of the pendulum at x = a/2 will be:

G1 Physics · Accepted Answer

Step 1: The speed at displacement x in SHM is v = ω√(a² − x²). Step 2: At x = a/2: v = ω√(a² − a²/4) = ωa√3/2. Step 3: Using ω = 2π/T, v = (2π/T)(a√3/2) = πa√3/T. Final answer: (D) πa√3/T.