The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic oscillation is:
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The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic oscillation is:

G1 Physics · Accepted Answer

Step 1: For x = A sin(ωt), velocity v = Aω cos(ωt) = Aω sin(ωt + π/2). Step 2: Acceleration a = −Aω² sin(ωt) = Aω² sin(ωt + π). Step 3: The phase of acceleration exceeds that of velocity by π − π/2 = π/2. Step 4: Hence the difference is 0.5π rad. Final answer: (D) 0.5π.